F(x)=x^2+8-48

Solution for F(x)=x^2+8-48 equation:

(F)=F^2+8-48

We move all terms to the left:

(F)-(F^2+8-48)=0

We get rid of parentheses

-F^2+F-8+48=0

We add all the numbers together, and all the variables

-1F^2+F+40=0

a = -1; b = 1; c = +40;
Δ = b2-4ac
Δ = 12-4·(-1)·40
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{161}}{2*-1}=\frac{-1-\sqrt{161}}{-2}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{161}}{2*-1}=\frac{-1+\sqrt{161}}{-2}
$